A uniform metal wire of density p, cross-sectional area A and length i is stretched with a tension T. The speed of transverse wave in the wire is given by

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$\sqrt{(\frac{T}{ρl})}$

$\sqrt{(\frac{T}{Aρ})}$

$\sqrt{(\frac{Tl}{ρA})}$

$\sqrt{(\frac{Tρ}{Al})}$

answer is D.

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Detailed Solution

Volume of wire = Al
Mass of the wire $= Al \times ρ$
$Mass per unit length = (Al \times ρ / l) = Aρ Now v = \sqrt{(\frac{T}{m})} = \sqrt{(\frac{T}{Aρ})}$

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