A uniform metallic wire carries a current 1A, when 3.4V battery is connected across it. The mass of uniform metallic wire is 8.92×10−3 kg. Density is 8.92×103 kg/m3 and resistivity is 0.85×10−8 Ωm. The length of wire is

ρ=rAl=(VI)mdl2l=(VI)md.1ρl=3.41.8.9×10−38.92×103×10.85×10−8l=20 m

A uniform metallic wire carries a current 1A, when 3.4V battery is connected across it. The mass of uniform metallic wire is 8.92×10−3 kg. Density is 8.92×103 kg/m3 and resistivity is 0.85×10−8 Ωm. The length of wire is

ρ=rAl=(VI)mdl2l=(VI)md.1ρl=3.41.8.9×10−38.92×103×10.85×10−8l=20 m

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A uniform metallic wire carries a current 1A, when 3.4V battery is connected across it. The mass of uniform metallic wire is $8.92 \times 10^{- 3} k g .$ Density is $8.92 \times 10^{3} k g / m^{3}$ and resistivity is $0.85 \times 10^{- 8} Ω m .$ The length of wire is

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$l = 20.0 m$

$l = 5.0 m$

$l = 15.0 m$

$l = 6.8 m$

answer is D.

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$ρ = \frac{r A}{l} = \frac{(\frac{V}{I}) \frac{m}{d}}{l^{2}}$

$l = \sqrt{(\frac{V}{I}) \frac{m}{d} . \frac{1}{ρ}}$

$l = \sqrt{\frac{3.4}{1} . \frac{8.9 \times 10^{- 3}}{8.92 \times 10^{3}} \times \frac{1}{0.85 \times 10^{- 8}}}$

$l = 20 m$

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A uniform metallic wire carries a current 1A, when 3.4V battery is connected across it. The mass of uniform metallic wire is 8.92×10−3 kg. Density is 8.92×103 kg/m3 and resistivity is 0.85×10−8 Ωm. The length of wire is

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A uniform metallic wire carries a current 1A, when 3.4V battery is connected across it. The mass of uniform metallic wire is $8.92 \times 10^{- 3} k g .$ Density is $8.92 \times 10^{3} k g / m^{3}$ and resistivity is $0.85 \times 10^{- 8} Ω m .$ The length of wire is