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Q.

A uniform metallic wire has a resistance of $18 Ω$ and is bent into an equilateral triangle. Then the resistance between any two vertices of the triangle is

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a

$18 Ω$

b

$2 Ω$

c

$4 Ω$

d

$12 Ω$

answer is A.

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Detailed Solution

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$\frac{1}{Re q} = \frac{1}{12} + \frac{1}{6} \Rightarrow Re q = 4 Ω$

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