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A uniform metre scale of mass 2kg is suspended from one end. If it is displaced through an angle $60 °$ from the vertical, the increase in its potential energy is,

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4.9J

9.8 J

9.8 \sqrt{3} J

4 .9 (2 - \sqrt{3}) J

answer is A.

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Detailed Solution

W = mg \frac{l}{2} (1 - \cos θ)

$= 2 \times 9.8 \times \frac{1}{2} (1 - \frac{1}{2})$

$= 4.9 J$

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