A uniform rectangular wire frame has side lengths $AB=2L$ and $BC=L.$ A long straight wire carrying current $I$ joins the frame at $P$ such that $AP=\frac{L}{2}.$ The current exits into another long wire at $Q$ such that $CQ=\frac{L}{2}.$ A uniform magnetic field (B) exists in the entire space parallel to the frame. The direction of $\overrightarrow{B}$ is parallel to the two long wires. If the frame is released form this position, what will be its initial acceleration $\left(\mathrm{in}\mathrm{\hspace{0.17em}}\mathrm{m}.{\mathrm{s}}^{-2}\right)$ ? Mass of the frame is $m.$ Assume no other force apart from magnetic force. $\left(B=2T,m=3kg,L=1m,I=0.5A\right)$