$\tau =1\alpha mg\sin 45°\times \frac{\mathcal{l}}{2}=\frac{m{\mathcal{l}}^2}{3}\alpha \Rightarrow \alpha =\frac{3g}{2\sqrt{2}\mathcal{l}}$

Tangential acceleration of centre of mass  $\left(a_t\right)=\alpha \times \frac{\mathcal{l}}{2}=\frac{3g}{4\sqrt{2}}$

Radial acceleration of centre of mass  $\left(a_r\right)=\frac{m{\omega }^2\mathcal{l}}{2}=0\left(initially\omega is0\right)$

$$\begin{gathered} mg\sin 45°-N_{\perp }=m{a}_t=N_{\perp }=\frac{mg}{4\sqrt{2}} \\ -mg\cos 45°+N_{//}=m{a}_r\Rightarrow N_{//}=\frac{mg}{\sqrt{2}} \end{gathered}$$

Net hinge force   $\sqrt{N_{\perp }^2+N_{//}^2}=mg\frac{\sqrt{17}}{4\sqrt{2}}\Rightarrow \sqrt{34}=5.83N$