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A uniform ring of radius $R$ is rotated about its axis with constant linear speed with each of its particles. The ratio of electric field to magnetic field at a point $P$ on its axis of the ring distant $x = R$ from the centre of ring is ( $c$ is speed of light)
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$\frac{c^{2}}{v}$

$\frac{v^{2}}{c}$

$\frac{v}{c}$

$\frac{c}{v}$

answer is A.

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Detailed Solution

$E = \frac{1}{4 {πε}_{0}} \frac{q x}{2 {(R^{2} + x^{2})}^{\frac{3}{2}}} B = \frac{μ_{0} i R^{2}}{2 {(R^{2} + x^{2})}^{\frac{3}{2}}}$

where,

$1 = q f = q (\frac{V}{2 πR}) c = \frac{1}{\sqrt{ε_{0} μ_{0}}}$

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