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Q.

A uniform rod AB having mass 2m and length 2l  is kept on a smooth horizontal plane. This rod is orthogonally connected to a horizontal taut string whose other end has a connected particle of mass m. If particle is given initial horizontal velocity v0, perpendicular to string, then just after giving this velocity, the tension in the string is mv02nl . Then the value of n  is

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a

2

b

1

c

3

d

4

answer is C.

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Detailed Solution

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a=T2m;  Tl=2m(2l)212α

Acceleration of point
 A=a+lα=T2m+3T2m=2Tm
w.r.t  A particle M moves in circle
  from frame of A  T+m×2Tm=mv02l
 T=mv023l;  α=v026l;  α=v022l2

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