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A uniform rod is kept vertically on a horizontal smooth surface at $O$ . If it is rotated slightly and released, it falls down on the horizontal surface. The lower end will remain :

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at $O$

at a distance less than $\frac{l}{2}$ from $O$

at a distance $\frac{l}{2}$ from $O$

at a distance larger than $\frac{l}{2}$ from $O$

answer is C.

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Detailed Solution

The forces that act on the rod the gravitational force and the normal reaction of the surface on the lower end . Since both of these forces are vertical, its C.G. falls vertically at $O$ .

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