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A uniform rod of length 1 m and mass 2 kg rotates in a horizontal plane at an angular speed of 6 rad/s, about an axis perpendicular to its length and passing through one of its ends. Then the tension induced at its mid-point is

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$18 N$

$48 N$

$32 N$

$27 N$

answer is D.

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Detailed Solution

Cl is the midpoint of the part BC.

$T_{C} = \frac{m}{2} . ω^{2} . r = (\frac{2}{2}) {(6)}^{2} . \frac{3}{4} N = 27 N$

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