A uniform rod of length $2 m$ . Velocity of point ‘$B$ ’ is $10 m/s$  as shown in figure and angular velocity of rod is $7 rad/s.$  Then

Let velocity at end $A$ is $v.$ 

The components of velocities at ends, along the length of the rod should be equal,

$10 \cos {37}^{\circ }=v\cos \theta$ ......(1)

And angular velocity, $\omega =\frac{v\sin \theta +6}{\mathrm{L}}$.......(2)

From eqs (i) and (ii), we get   $v=8\sqrt{2}\mathrm{m}/\mathrm{s}$

Now from eq. (i)

$\cos \theta =\frac{10\cos {37}^{\circ }}{v}=\frac{10\times 4/5}{8\sqrt{2}}=\frac{1}{\sqrt{2}}\Rightarrow \theta ={45}^{\circ }$