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A uniform rod of length 2m and mass 5kg is lying on a horizontal surface. The work done in raising one end of the rod with the other end in contact with the surface until the rod makes an angle 30^o with the horizontal is, (g = 10ms^–2)

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25J

50J

\sqrt{3}

\sqrt{3}

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detailed solution

Correct option is A

$w = mgh = mg \frac{l}{2} sinθ = 5 \times 10 \times \frac{2}{2} \times \frac{1}{2} = 25 J$

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A uniform rod of length 2m and mass 5kg is lying on a horizontal surface. The work done in raising one end of the rod with the other end in contact with the surface until the rod makes an angle 30o with the horizontal is, (g = 10ms–2)

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Ready to Test Your Skills?

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A uniform rod of length 2m and mass 5kg is lying on a horizontal surface. The work done in raising one end of the rod with the other end in contact with the surface until the rod makes an angle 30^o with the horizontal is, (g = 10ms^–2)