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A uniform rod of length L and mass m is free to rotate about a frictionless pivot at one end as shown in figure. The rod is held at rest in the horizontal position and a coin of mass m is placed at the free end. Now, the rod is released. The reaction on the coin immediately after the rod starts falling is

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(3) zero

(4) $\frac{mg}{2}$

(2) 2 m g

(1) $\frac{3 mg}{2}$

answer is C.

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Detailed Solution

$α = \frac{τ_{net}}{I} = \frac{mg (\frac{l}{2}) + mgl}{({ml}^{2} / 3)}$

$= \frac{4.5 g}{l} a_{coin} = lα = 4.5 g mg - N = {ma}_{coin} N = mg - {ma}_{coin} = - 3.5 g$

Since, N can't be negative.

So, N=0 and coin can not remain in contact with rod.

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