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A uniform rod of length $1 m$ and mass $2 k g$ is suspended. The tension $T (i n N)$ in the string at the instant when the right string snaps is _. $(T a k e g = 10 m / s^{2} .)$

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$20$

$15$

$10$

$5$

answer is D.

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Detailed Solution

$M g - T = M a_{y} \dots (i)$

$T (\frac{L}{2}) = \frac{M L^{2}}{12} α \dots (i i)$

and $a_{y} = \frac{L}{2} α \dots (i i i)$

On solving, we get $T = \frac{M g}{4} = 5 N$

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