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A uniform rod of mass 0.3 kg and length 0.5 m rotates at a uniform angular speed of $2 r a d S^{- 1}$ about an axis perpendicular to the rod through an end. The kinetic energy of rod is

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$5 \times 10^{- 2} J$

$1.25 \times 10^{- 2} J$

$1.25 \times 10^{- 3} J$

$5 \times 10^{- 3} J$

answer is A.

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Detailed Solution

$E = \frac{1}{2} I ω^{2}$ and $I = \frac{m l^{2}}{3}$

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