A uniform rope of length l lies on a table. If the coefficient of friction is $μ$ , then the maximum length $l_{1}$ of the hanging part of the rope which can overhang from the edge of the table without sliding down is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

$\frac{l}{μ}$

$\frac{μ l}{(μ - 1)}$

$\frac{l}{(μ + 1)}$

$\frac{μ l}{(μ + 1)}$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

In critical case, weight of hanging part= force of friction on the part of rope lying on table.

$\frac{m}{l} . l_{1} g = μ \frac{m}{l} (l - l_{1}) g$

Solving this we get,

$l_{1} = (\frac{μ}{1 + μ}) l$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE