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Q.

A uniform rope of length L lies on a table. If the coefficient of friction is  μ, the maximum length of the hanging part of the rope from the edge of the table without sliding down is

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a

(μ+1)Lμ

b

μLμ−1

c

μLμ+1

d

μL

answer is D.

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Detailed Solution

In the critical case, weight of the hanging part = force of friction on the part of rope lying on table

∴    ml.l1g=μml(l−l1)g

Solving this, we get l1=(μ1+μ)l

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