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A uniform rope of mass 0.1 kg and length 2.45 m hangs from a ceiling. The speed of transverse wave in the rope at a point 0.2 m distant from the lower end.

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2.21 m/s

2.8 m/s

1.4 m/s

0.7 m/s

answer is C.

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Detailed Solution

$v = \sqrt{\frac{T}{μ}} = \sqrt{\frac{μ x g}{μ}} = \sqrt{x g} = \sqrt{0.2 \times 9.8} = 1.4 m / s$

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