A uniform rope of mass 5kg is moving vertically in the vertical stretched position with an upward force of 100N, acting at the upper end and a downward force of 70N acting at the lower end. The tension at mid-point of the rope is

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105 N

85 N

75 N

100 N

answer is B.

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Detailed Solution

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$100 - (70 + 5 \times g) = 5 a$
$a = - 4 m / s^{2}$
Tension $(T)$ at half rope then mass $= 2.5 k g$
So, $70 + 2.5 g - T = 2.5 \times 4$
$T = 85 N$

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