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Q.

A uniform rope of mass m hangs freely from a ceiling. A bird of mass M climbs up the rope with an acceleration a. The force exerted by the rope on the ceiling is

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a

Ma+g+mg

b

Ma+g

c

Ma+mg

d

dependent on the position of bird on the rope

answer is B.

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Detailed Solution

Net force exerted by the rope on the ceiling = force exerted by the rope itself on the ceiling + force exerted by the bird on the rope

T = T1​ + T2​

We have,

T1 ​= mg

T2 − Mg = Ma

⇒T2 = M(g + a)

∴T = M(g + a) + mg 

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