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A uniform rope of mass m hangs freely from a ceiling. A bird of mass M climbs up the rope with an acceleration a. The force exerted by the rope on the ceiling is

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a
Ma+mg
b
Ma+g+mg
c
Ma+g
d
dependent on the position of bird on the rope

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detailed solution

Correct option is B

Net force exerted by the rope on the ceiling = force exerted by the rope itself on the ceiling + force exerted by the bird on the rope

T = T1​ + T2

We have,

T1 ​= mg

T2 − Mg = Ma

⇒T2 = M(g + a)

∴T = M(g + a) + mg 

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