A uniform solid sphere of mass 27kg has a radius of 3m. A cavity of radius 1m and mass 1kg is made at a distance of 2m from the center of large sphere. Gravitational acceleration on 2kg mass at a distance of 5m from the center of solid sphere along the line joining the two centers is

$$\begin{gathered} \begin{array}{l}Gravitational field strength=\frac{Gm}{r^2};here universal gravitation cons\tan t=G=6.67\times {10}^{-11}N{m}^{2}K{g}^{-2}; mass=m; dis\tan ce=r\\ E_{net}=E_{\text{solid sphere }}-E_{\text{cavity }}\\ E_{net}=\frac{G\left(27\right)}{5^2}-\frac{G\left(1\right)}{3^2}\\ E_{net}=\left(\frac{243-25}{25\times 9}\right)G\\ E_{net}=\frac{218}{225}\times 6.67\times {10}^{-11}\end{array} \\ \begin{array}{l}{E}_{net}=6.46\times {10}^{-11}\mathrm{N}/\mathrm{kg}\\ \therefore \text{ Gravitational force is }\\ F=m\times E\\ a=\frac{F}{m}=E\\ a=6.46\times {10}^{-11}{\mathrm{ms}}^{-2}=acceleration of 2kg mass\end{array} \end{gathered}$$