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A uniform square plate ABCD is suspended with the help of two ideal strings P and Q. Find the acceleration of corner A (in $m / s^{2}$ ) of the plate just after the moment when the string Q is cut $(g = 10 m / s^{2})$ .

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Detailed Solution

$T . \frac{l}{2} = \frac{m l^{2}}{6} . α$
mg – T = ma
$α = \frac{3 T}{m l} = \frac{3}{m l} (m g - m a) a - \frac{l}{2} α = 0$
Question Image
$α = \frac{2 a}{l} = \frac{3 (g - a)}{l}$
5a = 3g
$a= \frac{3a}{5} {=6m/s}^{2}$

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