A uniform wheel is rolling without slipping on a horizontal surface. At a certain instant, its centre of mass has velocity 'v' and acceleration 'a' as shown in figure. P, Q and R are three points on the rim of the disc as shown in the figure. Acceleration of point:

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Q may be vertically downwards

R cannot be horizontal

P is vertically upwards

Some point on the rim may be horizontal leftwards

answer is A, B, C, D.

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Detailed Solution

ABCD
At A : for a rolling wheel,
Question Image

At B : If $\frac{V^{2}}{R} = a t h e n a_{B} m a y b e v e r t i c a l l y d o w n w a r d s$

$\begin{array}{l} T_{m g} = I α \\ M g \times \frac{L}{2} = \frac{M L^{2}}{3} α i . e . α = 3 g / 2 L \\ a = r α \end{array}$

$a = L α = \frac{3 g}{2}$

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