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Q.

A uniform wire of resistance 50 Ω  is cut into five equal parts. These parts are now connected in parallel. Then the equivalent resistance of the combination is

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a

250 Ω

b

12 Ω

c

6250 Ω

d

2 Ω

answer is A.

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Detailed Solution

R1=10 Ω,   R2=10 Ω=R3=R4=R5

1Req=110+110+110+110+110=510=12

∴Req=2 Ω

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