Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

A uniformly charged and infinitely long line having a liner charge density λ is placed at a normal distance y from a point O. Consider a sphere of radius R with O as the center and R > y. Electric flux through the surface of the sphere is

Question Image

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

zero

b

2λRε0

c

2λR2y2ε0

d

λR2+y2ε0

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

 Electric flux   SEds=qin ε0

qin, is the charge enclosed by the Gaussian surface, which, in the present case, is the surface of the given sphere. As shown, length AB of line lies inside the sphere. In ΔOOA,

 R2=Y2+OA2 OA=R2y2 and  AB=2R2y2

 Charge on length AB is 2R2y2×λ

Question Image

Therefore, electric flux is

  SEds=2λR2y2ε0

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon