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A uniformly charged conducting sphere of $4.4 m$ diameter has a surface charge density of $60 μ C m^{- 2}$ . The charge on the sphere is

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$7.3 \times 10^{- 3} C$

$3.7 \times 10^{- 6} C$

$7.3 \times 10^{- 6} C$

$3.7 \times 10^{- 3} C$

answer is D.

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Detailed Solution

Here $D = 2 r = 4.4 m$ ,

or $r = 2.2 m, σ = 60 μ C m^{- 2}$ ,

Charge on the sphere, $q = σ \times 4 π r^{2}$

$= 60 \times 10^{- 6} \times 4 \times π \times {(2.2)}^{2} = 3.7 \times 10^{- 3} C$

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