A uniformly tapering vessel is filled with a liquid of density 900 kg/m². The force that acts on the base of the vessel due to the liquid is: (10 ms^-2)

7.2 N

To determine the force exerted by a liquid on the base of a uniformly tapering vessel, we can use the hydrostatic pressure formula:

Pressure (P):

P = ρ × g × h

Where:

• ρ (rho) = density of the liquid (900 kg/m³)
• g = acceleration due to gravity (10 m/s²)
• h = height of the liquid column (0.4 m)

Calculating the pressure:

P = 900 kg/m³ × 10 m/s² × 0.4 m = 3,600 N/m²

Force (F):

F = P × A

Where A is the area of the base of the vessel (2 × 10^-3 m²)

Calculating the force:

F = 3,600 N/m² × 2 × 10^-3 m² = 7.2 N

Therefore, the force acting on the base of the uniformly tapering vessel due to the liquid is 7.2 N.