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Q.

A unit vector pependicular to the plane of 
a=2i-6j-3k, b=4i+3j-k is

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a

4i+3j-k26

b

2i-6j-3k7

c

3i-2j+6k7

d

2i-3j-6k7

answer is B.

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Detailed Solution

a×b=ijk2-6-343-1         =i(6+9)-j(-2+12)+k(6+24)         =15i-10j+30k         =5(3i-2j+6k) |a×b|=59+4+36=5×7 Unit vector=3i-2j+6k7

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