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A uranium nucleus (atomic number 92, mass number 238) emits an $α -$ particle and the resultant nucleus emits a $β^{-} -$ particle. If Z and A are the atomic and mass numbers of the final nucleus, then

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$Z = 90$

$Z = 91$

$Z = 234$

$A = 233$

answer is B, C.

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Detailed Solution

$_{92}^{238} X {\to_{}^{α}}_{90} Y^{234} {\overset{β^{-}}{\to}}_{91} Z^{234}$

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