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Q.

A value of θ0,π3 for which 1+cos2θsin2θ4cos6θcos2θ1+sin2θ4cos6θcos2θsin2θ1+4cos6θ=0 is

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a

7π36

b

7π24

c

π18

d

π9

answer is D.

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Detailed Solution

We have

open vertical bar table row cell 1 plus cos squared theta end cell cell sin squared theta end cell cell 4 cos 6 theta end cell row cell cos squared theta end cell cell 1 plus sin squared theta end cell cell 4 cos 6 theta end cell row cell cos squared theta end cell cell sin squared theta end cell cell 1 plus 4 cos 6 theta end cell end table close vertical bar equals 0

 

 

 

R2R2-R1, R3R3-R21+cos2θsin2θ4cos6θ-110-101=01+cos2θ·1-sin2θ(-1)+4cos6θ=02+4cos6θ=0cos6θ=-126θ=2π3,4π3θ=π9,2π9

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