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A variable force, given by the 2-dimensional vector F=3x2i^+4j^ acts on a particle. The force is in newton and x is in metre. What is the change in the kinetic energy of the particle as it moves from the point with coordinates (2, 3) to (3, 0) ? (The coordinates are in metres)

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a

–7 J

b

zero

c

+7 J

d

+19 J

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detailed solution

Correct option is C

W=F.ds=3x2i^+4j^.dxi^+dyj^
W=233x2dx+304dy=x323+4y30

W=27-8+40-3=19-12=7 J


 

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