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A variable, opposite external potential $(E_{ext})$ is applied to the cell $Zn |{Zn}^{2 +} (1 M) ∥ {Cu}^{2 +} (1 M)| Cu$ of potential 1.1 V. When $E_{ext} < 1.1 V$ and $E_{ext} > 1.1 V$ respectively, electrons flow from:

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anode to cathode and cathode to anode

cathode to anode and anode to cathode

cathode to anode in both cases

anode to cathode in both cases

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detailed solution

Correct option is A

The cell will function as a galvanic cell if $E_{ext} < 1.1 V$ , at which point electrons will flow from the anode to the cathode.

$E_{ext} > 1.1 V,$ causes electrons to flow from cathode to anode, causing the cell to function as an electrolytic cell.

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A variable, opposite external potential (Eext) is applied to the cell ZnZn2+(1M)∥Cu2+(1M)Cu of potential 1.1 V. When Eext <1.1V and Eext >1.1V respectively, electrons flow from:

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Ready to Test Your Skills?

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A variable, opposite external potential $(E_{ext})$ is applied to the cell $Zn |{Zn}^{2 +} (1 M) ∥ {Cu}^{2 +} (1 M)| Cu$ of potential 1.1 V. When $E_{ext} < 1.1 V$ and $E_{ext} > 1.1 V$ respectively, electrons flow from: