A vector $3\hat{i}+4\hat{j}$ rotates about its tail through an angle $37°$ in anticlockwise direction then the new vector is

Now we should check at what angle given vector is making

$\therefore \tan \theta =\frac{4}{3}$

$\theta =53°$

Now $\sqrt{3^2+4^2}=5$ rotates about its tail through angle$37°$ anti clockwise

direction

$\therefore$ Now vector is at y axis$5\hat{j}$