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A vector has a component of 15m in the +x direction, a component of 15m in the +y direction, and a component of 10m in the +z direction.

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The vector is $15 \vec{i} + 15 \vec{j} + 10 \vec{k}$

The vector is $15 \vec{i} - 15 \vec{j} + 10 \vec{k}$

The magnitude of vector is $\sqrt{550} u n i t$

The magnitude of vector is $\sqrt{610} u n i t$

answer is A, C.

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Detailed Solution

$\vec{A} = a_{x} \vec{i} + a_{y} \vec{j} + a_{z} \vec{k}$ = $15 \vec{i} + 15 \vec{j} + 10 \vec{k}$

$| \vec{A} | = \sqrt{{a_{x}}^{2} + {a_{y}}^{2} + {a_{z}}^{2}}$ = $\sqrt{550} u n i t$

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