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Q.

A vector of magnitude 51 which makes equal angles with the vectors a=13i-2j+2k, b=15-4i-3k and c=j, is

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a

5i-j+5k

b

-5i+j-5k

c

-5i+j+5k

d

-i-j+7k

answer is C.

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Detailed Solution

r=xi+yj+zk    r=51 r, a=r, b=r, c r.ar a=r.br b=r.cr c x-2y+2z3=-4x-3z5=y1=k      y=k x+2z=5k4x+8z=20k-4x-3z=5k-4x-3z=5kx=5k-10k=-5k                                   5z=25k                             z=5k x2+y2+z2=51    25k2+k2+25k2=51                                 k=±1 r =-5i+j+5k     or  5i-j-5k                 

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