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Q.

A vector a→=αi^+2j^+βk^, (α,β∈R ) lies in the plane of the vectors b→=i^+j^ and c→=i^+j^+4k^. If a→ bisects the angle between b→ and c→. Then

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a

a→.i^+3=0

b

a→.i^+1=0

c

a→.i^+4=0

d

a→.k^+2=0

answer is D.

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Detailed Solution

b^+c^=i+j2+i+j+4k32=132(4i+4j+4k)         =232(2i+2j+2k) α=2   β=2   no option satisfied b^-c^=i+j2-i+j+4k32=132(2i+2j-4k) α=2   β=-4

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A vector a→=αi^+2j^+βk^, (α,β∈R ) lies in the plane of the vectors b→=i^+j^ and c→=i^+j^+4k^. If a→ bisects the angle between b→ and c→. Then