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Q.

A vector b collinear with a=22ij+4k of length 10 is given by

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a

3(22ij+4k)

b

2(22ij+4k)

c

2(22i+j+4k)

d

2(22i+j4k)

answer is D.

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Detailed Solution

b=λa and 10=|b|=|λa|

   |a|2=8+1+16=25|a|=5|λ|=2b=±2(22ij+4k)

 

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