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A vehicle is being driven by the force of $2.5 \times 10^{10}$ N travelling at a constant speed of $2 m / s$ . It takes $2 minutes$ for the vehicle to reach a certain point.

Is it true that the work done is $6 \times 10^{12}$ $J$ .

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True

False

answer is A.

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Detailed Solution

The above statement is True.
Work done in moving a body

(W)

is equal to the product of force exerted on the body and the distance moved by the body in the direction of force. Mathematically,

W = F \times s

Where

F

is the force exerted and

s

is the displacement of the body in the direction of the force.
Also,

2 \min = 2 \times 60 s

\Rightarrow

= 120 s

We can find the distance travelled by the vehicle using the formula

Distance (s) = Speed \times Time

\Rightarrow s = 2 \times 120

\Rightarrow

s = 240 m / s

Therefore, work can be calculated as

W = 2.5 \times 10^{10} \times 240

\Rightarrow W = 6 \times 10^{12} J

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