A vehicle moves for 10 minutes at 20 ms^-1 due north and stops for five minutes. Then at continues due north at 40 ms^-1 for 20 minutes. Average speed in the entire journey.

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2.857 ms^-1

2857 ms^-1

28.57 ms^-1

285.7 ms^-1

answer is C.

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Detailed Solution

$\bar{S_{1}} = 20 \times 10 \times 60 j$
$\bar{S_{2}} = 0; \bar{S_{3}} = 40 \times 20 \times 60 j$
$ν_{Avg} = \frac{| \bar{S_{1}} | + | \bar{S_{2}} | + | \bar{S_{3}} |}{t_{1} + t_{2} + t_{3}}$ = $20 \times 60 \frac{(10 + 40)}{35 \times 60} = 28.57$

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