A vernier caliper has 1 mm marks on the main scale. It has 20 equal divisions on the vernier scale which match with 16 main scale divisions. For this vernier caliper, the least count is:

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0.02 mm

0.2 mm

0.05 mm

0.1 mm

answer is B.

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Detailed Solution

Main scale division (MSD) = 1 mm, Vernier scale division (VSD) = $\frac{16}{20}$ MSD
Least count= 1 MSD - 1 VSD
=1 mm $- \frac{16}{20}$ (1 mm) = $\frac{1}{5} mm$ = 0.2 mm.

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