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A vernier calipers which is used to measure length of a cylinder has 1 mm marks on the main scale. It has 10 equal divisions on the vernier scale which match with 8 marks of main scale. If main scale reading is 4 and vernier is 5 then the length of cylinder is $1.25 N \times 10^{- 3}$ m then the value of N is:

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answer is A.

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Detailed Solution

$10 V S D = 8 M S D$

$1 V S D = \frac{8}{10} M S D$

$\begin{array}{l} Least count = 1 M S D - 1 V S D = 1 - \frac{8}{10} = 0.2 mm \\ Length = 4 + 5 \times 0.2 = 5.0 mm \\ 1.25 N \times 10^{- 3} = 5.0 \times 10^{- 3} m . \\ N = 4 \end{array}$

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