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A vernier callipers having 1 main scale division = 0.1 cm is designed to have least count of 0.02cm. if n be the number of divisions on vernier scale and m be the length of vernier scale, then:

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n = 9, m = 0.4 cm

n = 10, m = 0.8 cm

n = 10, m = 0.5 cm

n = 10, m = 0.2 cm

answer is C.

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Detailed Solution

$\begin{array}{l} M . S . D . = 1 mm \\ L . C . = 0 .02 cm \\ = 0 .2 mm \\ L.C. = M . S . D . - V . S . D . \\ = 1 mm - \frac{m}{n} = 0 .02 \\ \Rightarrow \frac{m}{n} = 0 .08 \end{array}$

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