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Q.

A vertical electric field of magnitude 2×105 N/C just prevents a water droplet of mass 0.4 g from falling. The value of charge on the droplet will be (g=10 m/s2)

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a

2×10−9 C

b

2×10−8 C

c

3×10−9 C

d

10−8 C

answer is B.

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Detailed Solution

mg=Eq⇒q=mgE=0.4×10−3×102×105=2×10−8 C

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