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Q.

A vertical electric field of magnitude 4.9 ×10⁵ N/c just prevents a water droplet of a mass 0.1g from falling. The value of charge on the droplet will be (g = 9.8 m/s²)

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a

1.6×10^-9 c

b

0.5×10^-9 c

c

2.0×10^-9 c

d

3.2×10^-9 c

answer is B.

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Detailed Solution

$F = E q \Rightarrow m g = E q \Rightarrow q = \frac{m g}{E} = \frac{0.1 \times 10^{- 3} \times 9.8}{4.9 \times 10^{5}} = 2 \times 10^{- 9} C$

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A vertical electric field of magnitude 4.9 ×105 N/c just prevents a water droplet of a mass 0.1g from falling. The value of charge on the droplet will be (g = 9.8 m/s2)