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A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.

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48m

32m

55m

42m

answer is D.

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Detailed Solution

Height of pole=AB=6 m
Length of shadow of pole =BC=4 m
Length of shadow of tower=EF=28 m
In △ABC and △DEF
∠B=∠E=

90^{\circ}

∠C=∠F [

∵

same elevation]
∴△ABC∼△DEF by AA similarity criterion
So,

\frac{AB}{DE} = \frac{BC}{EF}

\frac{6}{DE} = \frac{4}{28}

DE = 6 \times 7

= 42 m

∴

height is 42m
correct option is 4.

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