A vertical ray of light strikes the reflecting surface of a plane mirror which is inclined to the horizontal at an angle of 45^o as shown in figure. If the mirror rotates anticlockwise through an angle of 15^o, then the angle of deviation of the reflected ray is

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90^o

60^o

30^o

40^o

answer is C.

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Detailed Solution

The reflected ray must be horizontal as shown in figure. If the mirror rotates through 15^o, the reflected ray will rotate anticlockwise through 30^o. Therefore new angle of deviation will be $180^{o} - (90^{o} + 30^{o}) i . e . 60^{o}$ .

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