A vertical ring of radius r and resistance R falls vertically. It is in contact with two vertical rails which are joined at the top. The rails are without friction and resistance. There is a horizontal uniform magnetic field of magnitude B perpendicular to the plane of the ring and the rails. When the speed of the ring is $υ$ , the current in the section PQ is

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\frac{8 Br υ}{R}

zero

\frac{2 Br υ}{R}

\frac{4 Br υ}{R}

answer is D.

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Detailed Solution

i = 4 \frac{B l V}{R} but l = 2 r

$∴ i = \frac{8 Brv}{R}$

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