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Q.

A vertical ring of radius r and resistance ‘R’ slips vertically between two frictionless and   resistance less vertical rails. The rails and joined at the top there is a uniform magnetic field  B perpendicular to the plane of ring and the rails. When the speed of ring is V the current in  the section PQ is xBrvR then x is.

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answer is 8.

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Detailed Solution

 Iduced   emf;ε=B(2r)VI
Resistance of each half of ring = R/2
As these are in parallel, the equivalent resistance =R/4
Current in the circuit= B(2r)ϑ(R/4)=8BrϑR

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A vertical ring of radius r and resistance ‘R’ slips vertically between two frictionless and   resistance less vertical rails. The rails and joined at the top there is a uniform magnetic field  B perpendicular to the plane of ring and the rails. When the speed of ring is V the current in  the section PQ is x BrvR then x is.