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A very long wire carrying a current $I = 5.0 A$ is bent at right angles. Find the magnetic induction at a point lying on a perpendicular normal to the plane of the wire drawn through the point of bending at a distance $l = 35 c m$ from it.

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$2.0 μ T$

$2.0 T$

$3.0 μ T$

$2 μ T$

answer is A.

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Detailed Solution

$B_{n e t} = \sqrt{B^{2} + B^{2}} = \sqrt{2} B$

where, $B = \frac{μ_{0} i}{4 πr} (\sin 0 ° + \sin 90 °)$

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