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A vessel at 1000 K contains CO₂ at 0.4 atm. If certain amount of CO₂ is converted into CO by the addition of graphite, the following equilibrium is established $\large C{O_2}\, + \,C\, \rightleftharpoons \,2CO$ , at a pressure of 0.6 atm,then equilibrium constant is

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0.2atm

0.05atm

0.8 atm

0.15 atm

answer is C.

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Detailed Solution

	CO₂ + C $⇌$ 2 CO
Initial moles	0.4 0
Moles at equilibrium	0.4 -x 2x

Total moles at equilibrium = 0.4 - x + 2x

At constant volume and temperature p $\infty$ n

0.4 -x +2x = 0.6

x = 0.2

$P_{{CO}_{2}}$ = 0.4 - x = 0.4 -0.2 =0.2 atm

$P_{CO}$ = 2x = 2 $\times$ 0.2 = 0.4 atm

K_p⁼ $\frac{{[P_{CO}]}^{2}}{[P_{{CO}_{2}}]} =$ $\frac{{[0.4]}^{2}}{[0.2]} = 0.8$ atm

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